lily9026 lily9026

24-09-2022
Chemistry

Answered

A piece of chalk (mainly calcium carbonate) is placed in 250. mL of 0.468 M HCI.
All the CaCO3 reacts, releasing carbon dioxide gas and leaving 250. mL of a clear solution.
20.00 mL of the solution is pipetted into another flask.
29.8 mL of 0.0576 M NaOH is required to titrate the HCI remaining in this 20.00-mL portion.
What was the original mass of CaCO3 in the piece of chalk

Answer :

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