Answered

Two factory plants are making TV panels. Yesterday, Plant A produced 4 times as many panels as Plant B. Three percent of the panels from Plant A and 2% of the panels from Plant B were defective. How many panels did Plant B produce, if the two plants together produced 980 defective panels?



Answer :

semsee45

Answer:

7000 panels.

Step-by-step explanation:

Let x be the number of panels produced by Plant B.

Therefore:

  • 4x = number of panels produced by Plant A.
  • x = number of panels produced by Plant B.

Given information:

  • Defective panels from Plant A = 3%
  • Defective panels from Plant B = 2%
  • Total number of defective panels = 980

Create an equation with the given information and defined variables, remembering to write the percentages in their decimal form:

[tex]\implies 0.03(4x) + 0.02x = 980[/tex]

To find the number of panels Plant B produced, solve the found equation for x:

[tex]\implies 0.03(4x) + 0.02x = 980[/tex]

[tex]\implies 0.12x + 0.02x = 980[/tex]

[tex]\implies 0.14x = 980[/tex]

[tex]\implies \dfrac{0.14x}{0.14} = \dfrac{980}{0.14}[/tex]

[tex]\implies x=7000[/tex]

Therefore, Plant B produced 7000 panels.

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