d) $39,950
8. The car is $39,950. Interest is 10.25% and you finance for 7 years.
Figure the payments if you put down a) $0 b) $2,000 c) $3,000 d)
$5,000



Answer :

[tex]\frac{10.25}{100}[/tex]Answer:

Step-by-step explanation:

The formula for simple interest is: A= P(1+in)

The formula for compound interest is: A=P[tex](1+i)^{n}[/tex]

A= amount after added interest

P= initial amount invested

i= interest rate

n= number of periods (in this case its 7 years)

*REMEMBER THIS FORMULA

a) A=0

P=?

i=10,25

n=7

(simple interest)

a) A= 0 (1 +[tex]\frac{10.25}{100}[/tex] ×7)

=0

b) A=2 000 (1 + [tex]\frac{10.25}{100}[/tex] ×7)

A=3435

c) A= 3 000( 1 + [tex]\frac{10.25}{100}[/tex] ×7)

A= 5152.5

d) 5000(1 + [tex]\frac{10.25}{100}[/tex] ×7)

= 8587.5

It's just a matter of substitution. I hope this helped.

Answer:

(a) $668.39

(b) $634.93

(c) $618.20

(d) $584.74

Step-by-step explanation:

Monthly Payment Formula

[tex]\sf PMT=\dfrac{Pi\left(1+i\right)^n}{\left(1+i\right)^n-1}[/tex]

where:

  • PMT = monthly payment.
  • P = loan amount.
  • i = interest rate per month (in decimal form).
  • n = term of the loan (in months).

Given:

  • P = $39.950 less any down payment.
  • i = 10.25% / 12 = 0.1025/12
  • n = 7 years = 7 × 12 = 84 months

Part (a)

Down payment = $0

⇒ P = $39,950

[tex]\implies \sf PMT=\dfrac{39950\left(\dfrac{0.1025}{12}\right)\left(1+\left(\dfrac{0.1025}{12}\right)\right)^{84}}{\left(1+\left(\dfrac{0.1025}{12}\right)\right)^{84}-1}[/tex]

[tex]\implies \sf PMT = 668.3892086[/tex]

Therefore, the monthly payment is $668.39.

Part (b)

Down payment = $2,000

⇒ P = $39,950 - $2,000 = $37,950

[tex]\implies \sf PMT=\dfrac{37950\left(\dfrac{0.1025}{12}\right)\left(1+\left(\dfrac{0.1025}{12}\right)\right)^{84}}{\left(1+\left(\dfrac{0.1025}{12}\right)\right)^{84}-1}[/tex]

[tex]\implies \sf PMT = 634.9279215[/tex]

Therefore, the monthly payment is $634.93.

Part (c)

Down payment = $3,000

⇒ P = $39,950 - $3,000 = $36,950

[tex]\implies \sf PMT=\dfrac{36950\left(\dfrac{0.1025}{12}\right)\left(1+\left(\dfrac{0.1025}{12}\right)\right)^{84}}{\left(1+\left(\dfrac{0.1025}{12}\right)\right)^{84}-1}[/tex]

[tex]\implies \sf PMT = 618.197278[/tex]

Therefore, the monthly payment is $618.20.

Part (d)

Down payment = $5,000

⇒ P = $39,950 - $5,000 = $34,950

[tex]\implies \sf PMT=\dfrac{34950\left(\dfrac{0.1025}{12}\right)\left(1+\left(\dfrac{0.1025}{12}\right)\right)^{84}}{\left(1+\left(\dfrac{0.1025}{12}\right)\right)^{84}-1}[/tex]

[tex]\implies \sf PMT = 584.735991[/tex]

Therefore, the monthly payment is $584.74.