Answer:
w1= -1.4, w2= 3
Step-by-step explanation:
I will assume that "x" is a w since there is no x within the question
Solution
w
1
=−
5
7
,w
2
=3
Alternative Form
w
1
=−1.4,w
2
=3
Evaluate
5×∣4w−1∣=5w+40
Simplify
5∣4w−1∣=5w+40
Rewrite the expression
5∣4w−1∣−5w−40=0
Separate the equation into 2 possible cases
5(4w−1)−5w−40=0,4w−1≥0
5(−(4w−1))−5w−40=0,4w−1<0
Evaluate
w=3,4w−1≥0
5(−(4w−1))−5w−40=0,4w−1<0
Evaluate
w=3,w≥
4
1
5(−(4w−1))−5w−40=0,4w−1<0
Evaluate
w=3,w≥
4
1
w=−
5
7
,4w−1<0
Evaluate
w=3,w≥
4
1
w=−
5
7
,w<
4
1
Find the intersection
w=3
w=−
5
7
,w<
4
1
Find the intersection
w=3 w=− 57
Solution
w
1
=−
5
7
,w
2
=3
Alternative Form
w 1=−1.4,w 2
=3
