The given equations have in one, (1/5) is the coefficient of x, in the second equation, (1/5) is the coefficient of (x + 2), while both equations equals 6. Therefore, the value of x is different in both equations which do not represent the same situation.
How the given equations be evaluated?
The given equations are presented as follows;
[tex]\frac{1}{5} \cdot x + 2 = 6...(1)[/tex]
[tex] \frac{1}{5} \cdot (x + 2) = 6...(2)[/tex]
Solving each equation for x gives;
For equation (1), x = 5×(6 - 2) = 20
x = 20
For equation (2), we have;
x = 6 × 5 - 2 = 28
x = 28
Given that the value of x in the given equations are different, the situations are different.
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