Answer :
According to the given function, we can throw it to the height of 6.6 m. So, yes we can throw it high enough to reach the ledge.
What is a Quadratic equation?
The given equation is quadratic. A quadratic equation is defined as an equation of a single variable with the highest power of 2. In general, the quadratic equation can be expressed as h(x)= [tex]ax^2- bx + c[/tex], where a, b and c are arbitrary constants. The solution for a quadratic equation is given by:
[tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
The maximum of a quadratic equation is given by:
= [tex]c-\frac{b^2}{4a}[/tex]
The length to be covered by throwing=6 meters
It is given that the height of the grappling hook you throw is a function h(t) = -4.9t² + 10t + 1.5
Here a =4.9, b = 10 and c = 1.5
The maximum of a quadratic equation is given by:
[tex]c-\frac{b^2}{4a}[/tex]
[tex]1.5-\frac{10^2}{4*(-4.9)}[/tex]
6.6
A throw can be made to reach the wall since the height of wall is less than the maximum value that is 6.6 m.
To know more about Quadratic equation visit:
https://brainly.com/question/17177510
#SPJ9
