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If the slope of a line and a point on the line are​ known, the equation of the line can be found using the​ slope-intercept form, y=mx+b. To do​ so, substitute the value of the slope and the values of x and y using the coordinates of the given​ point, then determine the value of b.
Using the above​ technique, find the equation of the line containing the points ​(​-2,8) and (4,-1)



Answer :

ogorwyne

The equation of the line containing the points ​(​-2,8) and (4,-1) is:

y = -3x/2 + 5

Given data

points ​(​-2,8) and (4,-1)

How to find the equation of the line with the points ​(​-2,8) and (4,-1)

From the equation of the straight line y = mx + c

The slope of the line m is solved by

m = ( y2 - y1 ) / ( x2 - x1 )

m = ( -1 - 8 ) / ( 4 - -2 )

m = (-9 ) / ( 6 )

m = -3/2

using the point ( 4, -1 ) we find the intercept as

y = mx + c

-1 = -3/2 * 4 + c

-1 = -3 * 2 + c

-1 = -6 + c

-1 + 6 = c

c = 5

Substituting the values of m = -3/2 and c = 5 to the equation y = mx + c gives the equation of the line. This is done as follows

y = mx + c

y = -3/2 * x + 5

y = -3x/2 + 5

Read more on equation of straight line here: https://brainly.com/question/18831322

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