Answer :

The equation that is parallel to 4x- 2y = 6 and passes through (0, 1) is y = 2x + 1

How to determine the linear equation?

The given parameters are

4x - 2y = 6

Divide through by 2

So, we have

2x - y = 3

Make y the subject of formula

So, we have

y = 2x + 3

A linear equation is represented as

y = mx + c

Where

Slope = m

This means that

m = 2

Parallel lines have equal slopes

So, the slope of the other line is

m = 2

The point on the line is given as (0, 1)

The equation is then calculated as

y = m(x- x1) + y1

So, we have

y = 2(x - 0) + 1

Evaluate

y = 2x + 1

Hence, the equation that is parallel to 4x- 2y = 6 and passes through (0, 1) is y = 2x + 1

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