Answer:
(41, 43, 45)
Step-by-step explanation:
You want three consecutive odd integers such that the sum of the first and third is 43 more than the second.
Let n represent the middle (second) of the integers. Then the first is (n-2) and the third is (n+2). The given relation can be written as the equation ...
(n -2) +(n +2) = n +43
Simplifying gives ...
2n = n +43
n = 43
n-2 = 41
n+2 = 45
The three integers are (41, 43, 45).
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Additional comment
When working consecutive integer problems, it often works well to let a variable represent the middle one, or their average value.