The given quadrilateral is not a parallelogram.
According to the statement
We have to find that the whether the quadrilateral is a parallelogram or not.
So, For this purpose, we know that the
A parallelogram is a special type of quadrilateral that has both pairs of opposite sides parallel and equal.
From the given information:
The coordinates of the vertices of quadrilateral ABCD are A(-6,-1), B(-5,2), C(-1.-5), and D(0.-2).
Then
To show that the diagonals are bisect each other, we have to find the midpoint of both diagonals and if the midpoint is same then they bisect each other.
So,
Midpoint of AC = Midpoint of BD
Midpoint of A(-6,-1),C(-1.-5) = Midpoint of B(-5,2),D(0.-2)
( -6-1/2 , -1-5/2) = (-5+0/2 , 2-2/0)
( -7/2 , -6/2) = (-5/2 , 0/2)
And these midpoints are not same then they do not bisect each other and then it is not a parallelogram.
So, The given quadrilateral is not a parallelogram.
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