The initial amount and rate of change given a table for a linear function are $1160 and -$30, respectively
The table of linear function represents the given parameter
On the table, we have the following points
(x, y) = (6, 980) and (12, 800)
The rate of change is calculated as
Rate = (y2 - y1)/(x2 - x1)
So, we have
Rate = (980 - 800)/(6 - 12)
Evaluate
Rate = -30
This means that the rate of change is -$22.5
The initial amount is calculated as
y = m(x - x1) + y1
Where
m = -30
So, we have
y = -30(x - x1) + y1
Using one of the points, we have
y = -30(x - 6) + 980
Set x = 0
So, we have
y = -30(0 - 6) + 980
Evaluate
y = 1160
Hence, the initial amount and rate of change given a table for a linear function are $1160 and -$30, respectively
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