Line g is shown on the graph.

coordinate plane with line g that passes through the points negative 3 comma 6 and 0 comma 5

What is the equation of the line in slope-intercept form that is perpendicular to line g and passes through the point (1, −2)? Show all necessary steps.



Answer :

The linear equation that defines the line G can be written as:

y = -(1/3)*x + 5

How to get the equation of the line G?

A general linear equation written in the slope-intercept form is:

y = a*x + b

Where a and b are real numbers, a is the slope and b is the y-intercept.

If we know that the line passes through two points (x₁, y₁) and (x₂, y₂), then the slope is:

a = (y₂ - y₁)/(x₂ - x₁)

In this case we know that the line passes through (-3, 6) and (0, 5), then the slope is:

a = (5 - 6)/(0 - (-3)) = -1/3

The linear equation is something like:

y = (-1/3)*x + b

We know that it passes through (0, 5), then:

5 = (-1/3)*0 + b

5 = b

We conclude that the linear equation can be written as:

y = -(1/3)*x + 5

If you want to learn more about linear equations:

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