The equation 24x2+25x−47aX−2=−8x−3−53ax−2

is true for all values of x≠2a
where a is a constant. What is the value of a?



Answer :

The value of the constant a in the given expression (24x² + 25x - 47)/(ax - 2) = −8x − 3 - 53/(ax - 2) is; a = -3

How to solve Algebraic Equations?

We are given the equation;

(24x² + 25x - 47)/(ax - 2) = −8x − 3 - 53/(ax - 2)

This can be simplified further as;

(24x² + 25x - 47)/(ax - 2) = [(−8x − 3)(ax - 2) - 53]/(ax - 2)

Now, multiply both sides by ax - 2 to get;

(24x² + 25x - 47)= [(−8x − 3)(ax - 2) - 53]

Multiply out the brackets to get;

24x² + 25x - 47 = -8ax² + 16x - 3ax + 6 - 53

24x² + 25x - 47 = -8ax² + 16x - 3ax - 47

24x² + 25x = -8ax² + 16x - 3ax

24x² + 25x = -8ax² + (16 - 3a)x

Thus;

16 - 3a = 25

3a = 16 - 25

a = -9/3

a = -3

Read more about Algebraic Equations at; https://brainly.com/question/723406

#SPJ1