Answer :

Finding the numeric value for the given function, we have that:

a) The angle of elevation in the first day of summer is of 87.5º and of winter is of 40.9º.

b) The angle of elevation in the first day of summer is of 49.5º and of winter is of 2.9º.

c) Both cities have the same change in the angle of elevation.

How to find the numeric value of a function/expression?

To find the numeric value of a function, we replace each instance of the variable by the desired value. This also is true for a function of multiple variables, in which each value is replaced by it's attributed value.

For this problem, the function for the angle of inclination is given as follows:

A(L,N) = 90 - L - 23.5cos[360(N + 10)/365]

In which:

  • L is the latitude.
  • N is the day of the year.

For item a, we have that the latitude is of L = 26, hence on the first day of summer, the angle is given by:

A(26, 172) = 90 - 26 - 23.5cos(360 x 182/365) = 90 - 26 + 23.5 = 87.5º.

On the first day of winter, the angle is given by:

A(26, 355) = 90 - 26 - 23.5cos(360 x 355/365) = 90 - 26 - 23.1 = 40.9º.

The angle of elevation in the first day of summer is of 87.5º and of winter is of 40.9º.

For item b, we have that the latitude is of L = 64, hence on the first day of summer, the angle is given by:

A(26, 172) = 90 - 64 - 23.5cos(360 x 182/365) = 90 - 64 + 23.5 = 49.5º.

On the first day of winter, the angle is given by:

A(26, 355) = 90 - 64 - 23.5cos(360 x 355/365) = 90 - 64 - 23.1 = 2.9º.

The angle of elevation in the first day of summer is of 49.5º and of winter is of 2.9º.

The changes are given as follows:

  • Brownsville: 87.5 - 40.9 = 46.6º.
  • Nome: 49.5 - 2.9 = 46.6º.

Both cities have the same change in the angle of elevation.

More can be learned about the numeric values of a function at brainly.com/question/28367050

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