If a ball is thrown straight upward with an initial velocity of 30.0 m/s, how
much time does it table to reach its maximum height?
(A) 1.0 s
(B)1.4 s
(C)1.5 s
(D) 3.0 s



Answer :

The time taken by the ball to reach the maximum height when ball is thrown straight upward is t = 1.5s.

Equation :

To find the time we must know the distance so to calculate the distance using formula,

v² = u² + 2 as

where,

v is final velocity

u is initial velocity

a is acceleration due to gravity

s is distance

As, we can see,

u = v = 30m/s

a = - 9.8 m/s²

s = ?

So, putting the values we get,

30²m/s = 30²m/s + 2 (9.8 m/s²) s

s = 30²m/s / 30²m/s + 2 (-9.8 m/s²)

s = 19.6

Now after getting to know the distance we can use the formula,

s = d/t

Where,

s is speed

d is distance

t is time

So, putting the values,

t = 30 / 19.6

t = 1.5s

Hence, the time taken by the ball to reach the maximum height is 1.5s.

To know more about  acceleration due to gravity :

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