C. To get system B, the second equation in system A was replaced by the sum of that equation and the first equation multiplied by -3. The solution to system B will be the same as the solution to system A.
System A :
x + 6y = 5 ..........(1)
3x - 7y = -35 ..........(2)
If we multiply the first equation by -3, then we will get :
3(x + 6y) = 3 (5)
⇒ -3x - 18y = -15 ..... (3)
Now the Sum of equation (2) and equation (3) is:
⇒ Sum : -12y =-50
Now if we replace the second equation in system A with this -12y =-50 , then we will get the system B.
Solution of system B:
x + 6y = 5 ..........(1)
-25y =-50
First we will take the second equation as there is only one variable 'y'. So, we will solve that equation for 'y'
-25y =-50
y = -2
Now for solving 'x', we will plug y= -2 into the first equation
x + 6y = 5
x + 6(-2) = 5
x -12 = 5
x = 12+ 5
x = 17
So, the solution of system B is (17, -2), that means the solution of both systems are same.
To learn more about Equation
visit - https://brainly.com/question/16450098
#SPJ9
