Answer :

Answer:

1. 13, 18, 23, 28, 33, 38, 43, 48, 53

Conjecture: Each term is 5 more than the previous term.

2. 512, 256, 128, 64, 32, 16, 8, 4, 2

Conjecture: Each term is half of the previous term.

3. 1, 8, 27, 64, 125, 216, 343, 512, 729

Conjecture: Each term is a cube. To find the nth term, cube n.

4. 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31

Conjecture: Each term is the next consecutive prime number.

5. Correct as is

6. 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89

Conjecture: Each term is the sum of the 2 previous numbers.

Step-by-step explanation:

1.

Given: 13, 18, 23, 28

We add 5 to each number

13 + 5 = 18

18 + 5 = 23

23 + 5 = 28

28 + 5 = 33

33 + 5 = 38

38 + 5 = 43

43 + 5 = 48

48 + 5 = 53

2.

Given : 512, 256, 128, 64

Divide each number by 2

512 ÷ 2 =256

256 ÷ 2 = 128

128 ÷ 2 = 64

64 ÷ 2 = 32

32 ÷ 2 = 16

16 ÷ 2 = 8

8 ÷ 2 = 4

4 ÷ 2 = 2

3.

Given: 1, 8, 27, 64

We have to cube n:

n³ = consecutive number cubed

1³ = 1 or 1 × 1 × 1

2³ = 8 or 2 × 2 × 2

3³ = 27 or 3 × 3 × 3

4³ = 64 or 4 × 4 × 4

5³ = 125 or 5 × 5 × 5

6³ = 216 or 6 × 6 × 6

7³ = 343 or 7 × 7 × 7

8³ = 512 or 8 × 8 × 8

9³ = 729 or 9 × 9 × 9

4.

Consecutive prime number: Consecutive prime numbers are those that have no gaps or prime numbers between them.

Look at the picture in the link:

6.

Given: 1, 1, 2, 3, 5, 8

We must add the two previous numbers to get the next term:

1 + 1 = 2

1 + 2 = 3

2 + 3 = 5

3 + 5 = 8

5 + 8 = 13

8 + 13 = 21

13 + 21 = 34

21 = 34 = 55

34 + 55 = 89

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