Answer :
The equation of the line is y=x+12.
What is line?
A line is a straight one-dimensional figure having no thickness and extending infinitely in both directions. A line is made of a set of points which is extended in opposite directions infinitely. It is determined by two points in a two-dimensional plane. The two points which lie on the same line are said to be collinear points.
Given:
The points are
(-3,9)=[tex](x_{1} ,y_{1} )[/tex] and (-9,3)=[tex](x_{2} ,y_{2} )[/tex]
We have to Write the equation of the line.
According to given question we have,
Equation of line passing through the point (-3,9) and (-9,3).
Slope of the line=
[tex]\frac{y_{2}-y_{1} }{x_{2} -x_{1} } \\\\=\frac{3-9}{-9+3} \\\\=\frac{-6}{-6} \\\\=1[/tex]
⇒y−9=1(x+3)
⇒y-9=x+3
Add 9 on both sides we get,
y=x+12
∴ y=x+12 which is in the form y=mx +c is the required equation.
Therefore, the equation of the line is y=x+12.
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y = x + 12
What is equation of a line?
The standard form of equation of a line is ax + by + c = 0. Here a, b, are the coefficients, x, y are the variables, and c is the constant term. It is an equation of degree one, with variables x and y. The values of x and y represent the coordinates of the point on the line represented in the coordinate plane.
y-y₁=m(x-x₁)
mm₁=-1
Points (-3,9) and (−9,3).
Slope of the line m = (y₂ - y₁)/(x₂ - x₁)
m = (3-9)/(-9+3)
m = 1
Now equation of line passing through two points
(y - y₁)/(y₂ - y₁) = m*(x - x₁)/(x₂ - x₁)
(y - 9)/(3-9) = 1*(x - 3)/(-9+3)
y - 9 = x + 3
y = x + 12
Therefore, the equation of line is y = x + 12
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