The numerical length and width of the rectangular picture are 9in and 12in respectively.
Area of a rectangle is expressed as;
A = length × width
Given the data in the question;
To determine the numerical length and width of the rectangular picture, first plug the given values into the equation and solve for x.
A = length × width
108 = (2x -1)(x+7)
Expand
108 = 2x² + 14x - 1x -7
108 = 2x² + 13x -7
Reorder
2x² + 13x -7 = 108
2x² + 13x - 7 - 108 = 0
2x² + 13x - 115 = 0
Solve by grouping
(x-5)(2x+23) = 0
x-5 = 0, 2x+23 = 0
x = 5, 2x = -23
x = 5, x = -23/2
x = 5, x = -11.5
But the dimension cannot be negative, hence;
x = 5
Next, determine the numerical length and width.
Length = 2x - 1 = 2(5) - 1 = 10 - 1 = 9in
Width = x + 7 = 5 + 7 = 12in
Therefore, the numerical length and width of the rectangular picture are 9in and 12in respectively.
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