The largest possible value of n is approximately equal to 331.
In this problem we find a factorial number as the result of a power with a base of 3. First, we need to estimate the maximum possible value of n (as a real number) by using logarithm properties:
3ⁿ = 100!
3ⁿ = 1 · 2 · 3 · ... · 99 · 100
㏒₃ 3ⁿ = ㏒₃ (1 · 2 · 3 · ... · 99 · 100)
n · ㏒₃ 3 = ㏒₃ 1 + ㏒₃ 2 + ㏒₃ 3 + ... + ㏒₃ 99 + ㏒₃ 100
n ≈ 331.090
Second, find the maximum possible integer n related to 100! is found by truncating the result found in the previous section. Hence, the largest possible value of n is approximately equal to 331.
To learn more on factorials: https://brainly.com/question/16674303
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