The Vertex is at (3, 0)
The Axis of symmetry is; x = 3
The x-intercept is; x = 3
We are given the quadratic equation as;
y = -2(x - 3)²
Expanding this gives us;
y = -2(x² - 6x + 9)
y = -2x² + 12x - 18
x coordinate of vertex = -b/2a = -12/(2 * -2) = 3
y coordinate of vertex = f(3) = -2(3)² + 12(3) - 18 = 0
Vertex is at (3, 0)
Axis of symmetry is the x coordinate of vertex = -b/2a = -12/(2 * -2) = 3
x-intercepts is gotten by finding the roots which are; x = 3 and 3
Read more about Vertex and Axis of Symmetry at; https://brainly.com/question/15709421
#SPJ1