The problem is:
y = -2(x-3)^2

Please help me find the;
Vertex,
X-Intercepts,
and the Axis of Symmetry

Alg 2, Intercept, Vertex form.



Answer :

The Vertex is at (3, 0)

The Axis of symmetry is; x = 3

The x-intercept is; x = 3

What is the Vertex and Axis of Symmetry?

We are given the quadratic equation as;

y = -2(x - 3)²

Expanding this gives us;

y = -2(x² - 6x + 9)

y = -2x² + 12x - 18

x coordinate of vertex = -b/2a = -12/(2 * -2) = 3

y coordinate of vertex = f(3) = -2(3)² + 12(3) - 18 = 0

Vertex is at (3, 0)

Axis of symmetry is the x coordinate of vertex = -b/2a = -12/(2 * -2) = 3

x-intercepts is gotten by finding the roots which are; x = 3 and 3

Read more about Vertex and Axis of Symmetry at; https://brainly.com/question/15709421

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