a) If the [tex]n[/tex]-th term is [tex]x_n = cn+d[/tex], then
[tex]x_1 = c + d = 16[/tex]
[tex]x_2 = 2c + d = 19[/tex]
Eliminating [tex]d[/tex],
[tex](2c+d) - (c+d) = 19-16 \implies c = 3[/tex]
Solving for [tex]d[/tex],
[tex]3 + d = 16 \implies d = 13[/tex]
Then
[tex]\boxed{x_n = 3n + 13}[/tex]
b) When [tex]n=11[/tex], we get
[tex]x_{11} = 3\cdot11 + 13 = \boxed{46}[/tex]