Mel1on
Answered

finding perimeter 15 3/14, 12 2/7, 35 3/7, 10 1/7, 24 1/14, 12 2/7, 10 1/7 i have the first part so far, now all i would need is the fraction
119 [ / ]

finding perimeter 15 314 12 27 35 37 10 17 24 114 12 27 10 17 i have the first part so far now all i would need is the fraction119 class=