assuming I = E(R + r), prove that I/I = R/E + r/E

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18-09-2022
Mathematics

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assuming I = E(R + r), prove that I/I = R/E + r/E

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varshamittal029 varshamittal029 · Answer 1 · 2022-09-21T05:47:58-04:00

If we assume that I = E(R + r), then I/I = R/E + r/E.

The inverse of a value of a number is known as the reciprocal of the number. The reciprocal can be found out by replacing the numerator with the denominator and vice versa. For example, reciprocal of a number x will be 1/x and vice versa.

Here, we are given that I = E/(R + r)

Taking reciprocals of both sides we get-

Reciprocal of I will be- 1/I

Reciprocal of E/(R + r) will be- (R + r)/ E

Thus,

1/I = (R + r)/ E

Simplifying the equation further, we get-

1/I = R/E + r/E

Hence, proved

Learn more about reciprocals here-

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assuming I = E(R + r), prove that I/I = R/E + r/E​

Answer :

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assuming I = E(R + r), prove that I/I = R/E + r/E