The price of a :
Senior citizen ticket = $4
Child ticket = $16.8
On the first day school sold,
Senior citizen ticket = 14
Child ticket = 14
Total Price = $252
On the second day school sold,
Senior citizen ticket = 9
Child ticket = 7
Total Price = $154
Let the price of ticket for senior citizen = ‘s’
And, for child = ‘c’
By first day, we get
14s + 14c = 252 ... eq.( 1 )
By second day, we get
9s + 7c = 154 ... eq.( 2 )
Multiply eq.( 2 ) by 2, we get
18s + 14c = 308 ... eq.( 3 )
Now, we will subtract eq.( 1 ) by eq.( 3 ),
18s + 14c = 308
- 14s - 14c = -252
______________
4s = 56 ( Divide both side by 4 )
s = 14
So, the ticket price of one senior citizen is $4.
To determine the ticket price of one senior citizen, we will solve the eq. 2 by putting s = 4
So, 9s + 7c = 154
(9 × 4) + 7c = 154
36 + 7c = 154
7c = 154 - 36 = 118 ( By dividing both side by 7 )
c = 16.8
Hence, the ticket price of one child is $16.8 .
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