The perimeter of the triangle shown is 556 meters. Find
the length of each side.
x meters =
4x meters =
(8x - 3) meters =
(Type integers or decimals.)
4x meters
(8x - 3) meters
x meters

The perimeter of the triangle shown is 556 meters Find the length of each side x meters 4x meters 8x 3 meters Type integers or decimals 4x meters 8x 3 meters x class=


Answer :

The sides of the triangle are as  follows:

a = 43 meters

b = 172 meters

c = 341 meters

Given, we have the perimeter of the triangle as 556 meters.

The sides of the triangle are:

a = x meters

b = 4x meters

c = (8x - 3) meters.

we know that perimeter of the triangle = a + b + c

therefore, a + b+ c = Perimeter

x + 4x + (8x - 3) = 556

x + 4x + 8x - 3 = 556

13x - 3 = 556

13x = 556 + 3

13x = 559

x = 559/13

x = 43

hence we get the value of x as 43.

substitute x value in the sides of the triangle to get the orignal values of the sides.

a  = x = 43 meters.

b = 2x = 4 × 43 = 172 meters.

c = 8x - 3 = 8(43) - 3 = 341 meters.

Hence the sides of the triangle are 43 meters , 172 meters and 341 meters.

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