The mass of barium carbonate containing 10% impurities if 6.72 liters of CO₂ were formed when hydrochloric acid was added to it is 65.78 g.
The mass of barium carbonate containing 10% impurities that produced 6.72 liters of CO₂ when hydrochloric acid was added to it is determined from the equation of the reaction as follows:
Equation of the reaction: BaCO₃ + 2 HCl → BaCl₂ + H₂O + CO₂
Based on the equation of the reaction, 1 mole of barium carbonate produces 1 mole of CO₂.
1 mole of CO₂ has a volume of 22.4 liters
6.72 liters of CO₂ = 6.72/22.4 moles
6.72 liters of CO₂ = 0.3 moles
Moles of BaCO₃ reacted = 0.3 moles
Molar mass of BaCO₃ = 197.34 g/mol
Mass of 0.3 moles of BaCO₃ = 0.3 * 197.34 g/mol
Mass of 0.3 moles of BaCO₃ = 59.2 g
Since the barium contains 90% pure BaCO₃ and 10% impurity,
Mass of barium carbonate reacted = 59.2 g/0.9
Mass of barium carbonate reacted = 65.78 g
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