Answer:
Function 1 is neither odd nor even
Function 2 is odd
Step-by-step explanation:
Here, you must first understand the expression of odd and even functions:
Even: f(x) = f(-x)
Odd: f(-x) = -f(x)
Question 1:
[tex]{ \tt{f(x) = x + 3}} \\ { \rm{when \: x = - x}} \\ { \tt{f( - x) = - x + 3}} \\ { \tt{f( - x) \: is \: neither \: even \: nor \: odd }}[/tex]
Question 2:
[tex]{ \tt{f(x) = - { \green{{3x}^{3} + 6x }}}} \\ { \rm{when \: x = - x}} \\ { \tt{f( - x) = - 3 {( - x)}^{3} + 6( - x) }} \\ { \tt{f( - x) = 3 {x}^{3} - 6x}} \\ { \tt{f( - x) = - \{ { \green{- 3 {x}^{3} + 6x }}}} \} \\ { \tt{f( - x) = - f(x)}}[/tex]
