the perimeters of two squares are in the ratio 2 : 7. What is the ratio of the area of the smaller square to the area of the larger square



Answer :

Area of smaller square : Area of larger square = 4 : 49

Area of Squares

Perimeter of small square = [tex]P_1[/tex]

Perimeter of  large square = [tex]P_2[/tex]

P = 4L

[tex]P_1=4L_1\\\\P_2=4L_2[/tex]

Perimeter Ratio = 2:7

[tex]\frac{4L_1}{4L_2} =\frac{2}{7} \\\\\frac{L_1}{L_2} =\frac{2}{7}[/tex]

Area of a square = Length^2

[tex](\frac{L_1}{L_2} )^2=(\frac{2}{7} )^2\\\\\frac{L_{1} ^{2} }{L_{2} ^{2}} =\frac{2^2}{7^2} \\\\\frac{L_{1} ^{2} }{L_{2} ^{2}} =\frac{4}{49}[/tex]

Therefore, the ratio of the area of the smaller square to the area of the larger square = 4 : 49

Learn more on perimeters and area of squares here: https://brainly.com/question/25092270

#SPJ1