Answer:
[tex] \frac{2 x - 1 + y }{2x + y + 1} [/tex]
Step-by-step explanation:
In the expression:
[tex] \frac{4 {x}^{2} - {y}^{2} - 4x + 1 }{4 {x}^{2} - {y}^{2} - 2y - 1 } [/tex]
Reorder the terms
[tex]⟹\frac{(4 {x}^{2} - 4x + 1) - {y}^{2} }{4 {x}^{2} - {y}^{2} - 2y - 1 } [/tex]
Rewrite the expression
[tex]⟹ \frac{(2x {)}^{2} - 2 \times 2x + {1}^{2} - {y}^{2} }{ {4x}^{2} - {y}^{2} - 2y - 1 } [/tex]
Factor the expression
[tex]⟹ \frac{(2x - 1 {)}^{2} - {y}^{2} }{4 {x}^{2} - {y}^{2} - 2y - 1 } [/tex]
[tex]⟹ \frac{((2x - 1) + y)((2x - 1) - y)}{4 {x}^{2} - {y}^{2} - 2y - 1} [/tex]
Reorder terms
[tex] \frac{((2x - 1) + y)((2x - 1) - y)}{ {4x}^{2} + ( - {y}^{2} - 2y - 1} [/tex]
Factor greatest common factors out
[tex] \frac{((2x - 1) + y)((2x - 1) - y)}{ {4x}^{2} - ( {y}^{2} + 2y + 1) } [/tex]
Rewrite the expression
[tex] \frac{((2x - 1) + y)((2x - 1) - y)}{ {4x}^{2} - ( {y}^{2} + 2y + {1}^{2}) } [/tex]
Factor the expression
[tex] \frac{((2x - 1) + y)((2x - 1) - y)}{ {4x }^{2} - (y + 1)} [/tex]
I'm sorry for breaking but it's a very long explanation
