Answer :

The number of integers that satisfies the inequalities, -5 ≥ -7•x and -15 ≥ 5•x is zero or non

How can the inequalities be simplified?

The given inequalities are;

-5 ≥ -7•x and -15 ≥ 5•x

Simplifying the inequalities gives;

-5 ≥ -7•x

Dividing both sides by -7 gives;

-5/-7 ≤ -7•x/-7 = x

Therefore;

5/7 ≤ x

Which gives;

  • x ≥ 5/7

The second inequality is simplified as follows;

-15 ≥ 5•x

-15/5 ≥ 5•x/5

-3 ≥ x

Which gives;

x ≤ -3

Therefore;

-3 ≥ x and x ≥ 5/7

5/7 ≤ x ≤ -3

However, 5/7 > -3

The number of integers that satisfies the inequality, 5/7 ≤ x ≤ -3, is zero (no integer satisfies the inequality).

Therefore;

Non of the integers satisfies both -5 ≥ -7•x and -15 ≥ 5•x

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