The function f(x) = x^4 + 4/x^2 + 1 is an even function
The equation of the function is given as
f(x) = x^4 + 4/x^2 + 1
Calculate f(-x)
So, we have
f(-x) = (-x)^4 + 4/(-x)^2 + 1
Evaluate the exponents
f(-x) = x^4 + 4/x^2 + 1
Calculate -f(x)
So, we have
-f(x) = -[x^4 + 4/x^2 + 1]
Evaluate the product
-f(x) = - x^4 + 4/x^2 + 1
From the above computations, we have
f(x) = f(-x)
This represents an even function
Hence, the function f(x) = x^4 + 4/x^2 + 1 is an even function
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