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Write an equation of the line passing through the point (6,3) that is perpendicular to the line 6x+5y=10

An equation of the line is
y = ?x + ?

Write an equation of the line passing through the point 63 that is perpendicular to the line 6x5y10 An equation of the line is y x class=


Answer :

angstar4
Put equation in slope intercept form
6x+5y=10
5y=-6x+10
y=-6/5x+2

Perpendicular lines have opposite reciprocal slopes
Slope = 5/6

Use point slope formula
Y2-y1=m(x2-x1)
y-3= 5/6(x-6)
y-3=5/6x= -1

y = 5/6x +5

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