The probability that the 3 outcome of numbers obtained are three consecutive numbers is 1/9.
What is defined as the probability?
The probability of an event occurring is calculated by dividing the amount of favourable outcomes by total number of possible outcomes.
Now, as per the given question;
- The first number must be either 1, 2, 3, or 4, with a probability; 4/6 = 2/3.
- The second number must be one higher, which occurs with a probability of 1/6.
- The third number must then be one greater than the second, which occurs with a probability of 1/6.
- Therefore the answer to the question about the order; (2/3)×(1/6)×(1/6) = 2/108.
To address your point, if the three numbers seem to be different, there are 3! = 6 different orders in which they could have been placed.
As a result, the solution to the question;
= (2/3)×(1/6)×(1/6)×6
= (2/3)(1/6)
= 1/9.
Therefore, the probability of getting the three consecutive number is 1/9.
To know more about the probability, here
https://brainly.com/question/13604758
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