Answer :
From given A={a,b,c,d,e,h}, B={b,c,d,f,g} and C= {a,c,e,f,h,i}
result related to union and intersection of sets are verified
A). A- (B∪C)=(A - B)∩ (A- C)
B). A∩(B-C) =(A∩B) - (A∩C)
As given,
A={a,b,c,d,e,h}
B={b,c,d,f,g}
C={a,c,e,f,h,i}
A). A- (B∪C)={a,b,c,d,e,h} - { a,b,c,d,e,f,g,h,i}
= { }
(A - B)∩ (A- C)={a,e,h} ∩ {b,d}
={ }
⇒A- (B∪C)=(A - B)∩ (A- C)
B) A∩(B-C)={a,b,c,d,e,h} ∩{b,d,g}
={b,d}
(A∩B) - (A∩C)={b,c,d} -{a,c,e}
={b,d}
⇒A∩(B-C)=(A∩B) -(A∩C)
Therefore, from given A={a,b,c,d,e,h}, B={b,c,d,f,g} and C= {a,c,e,f,h,i}
result related to union and intersection of sets are verified
A). A- (B∪C) =(A - B)∩ (A- C)
B). A∩(B-C)=(A∩B) - (A∩C)
The complete question is:
If A={a,b,c,d,e,h}, B={b,c,d,f,g} and C= {a,c,e,f,h,i}, then verify that
A). A- (B∪C) = (A - B)∩ (A- C)
B). A∩(B-C) = (A∩B) - (A∩C)
Learn more about intersection of sets here
brainly.com/question/14679547
#SPJ1
