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A set contains 23 elements set B contains 15 elements, and 13 elements are common to sets A and B how many elements are in set A



Answer :

A contains 21 elements

Let's assume set A contains X elements ,

so , according to set theory ,  A ∪ B = 23

or, A + B - ( A ∩ B ) = 23

or ,X + 15 - 13 = 23

or, X + 2 = 23

or , X =  23 - 2

or, X = 21

So , there are 21 elements are present in set A .

To know more about set theory ,

https://brainly.com/app/ask?q=set+theory

Solving the problem according to the set theory, we get that set A contains 21 elements.

A set is a well-defined collection of objects, whose elements remain fixed and do not vary. It means that set doesn't change from person to person and is invariable.

Let's assume that set A contains X elements,

So, according to the set theory, A ∪ B = 23

or, A + B - ( A ∩ B ) = 23

or ,X + 15 - 13 = 23

or, X + 2 = 23

or , X = 23 - 2

or, X = 21

From the above explanation, we get that there are 21 elements are present in set A .

To know more about set theory, refer to the following link:

https://brainly.com/question/13205223

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