The length of the segment BC is equal to 5√3 π / 3.
Herein we find the a geometric system formed by a circle and an inscribed right triangle formed by two right triangles. By a quick inspection we find the following measures:
AD = 10π, m ∠ BCD = 60°, m ∠ BDC = 30°, m ∠ BDA = 60°, m ∠ BAD = 30°
Then, by 30-60-90 right triangle theorem we find that:
DB = (1 / 2) · AD
DB = (1 / 2) · 10π
DB = 5π
DB = √3 · BC
BC = (√3 / 3) · DB
BC = 5√3 π / 3
The length of the segment BC is equal to 5√3 π / 3.
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