An airplane is preparing to land at an airport. It is46,400 feet above the ground and is descending at the rate of3,100 feet per minute. At the same​ airport, another airplane is taking off and will ascend at the rate of 2,700 feet per minute. When will the two airplanes be at the same altitude and what will that altitude​ be?

An airplane is preparing to land at an airport It is46400 feet above the ground and is descending at the rate of3100 feet per minute At the same airport another class=


Answer :

The time when the two airplanes would have the same altitude is 8 minutes. The altitude would be 21,600 feet.

What is the altitude?

The equation that can be used to represent the altitude of the descending plane is: feet above the ground - (rate of descent x number of minutes)

46,400 - (3100 x t)

The equation that can be used to represent the altitude of the ascending plane is: rate of ascent x number of minutes

2700 x t

Where t is the number of minutes

When both airplanes are of the same altitude, the above equations will be equal: 2700t = 46,400 - 3100t

In order to determine the value of t, take the following steps:

Combine similar terms: 2,700t + 3,100t = 46,400

Add similar terms : 5,800t = 46,400

Divide both sides by 5,800 : t = 46,400 / 5,800

t = 8 minutes

Altitude = 2700 x 8 = 21,600 feet

To learn more about mathematical equations, please check: https://brainly.com/question/26427570

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