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Gold can be hammered into extremely thin sheets called gold leaf. An architect wants to cover a 100 ft x 28 ft ceiling with gold leaf that is five-millionths of an inch thick. The density of gold is 19.32 g/cm^3, and gold costs $1654 per troy ounce ( 1 troy ounce =31.1035 g). How much will it cost the architect to buy the necessary gold?



Answer :

Lanuel

Based on the calculations, it would cost the architect $33,940.08 to buy the necessary gold.

What is density?

Density can be defined as a ratio of mass to the volume of an object such as a baseball. Mathematically, the density of a baseball can be calculated by using this formula:

Density = M/V

Where:

  • M represents the mass of a physical object.
  • V represents the volume of a physical object.

How to determine the cost of gold needed?

First of all, we would determine the volume of gold that is required in cubic centimeters as follows:

Conversion factor:

12 inches = 1 foot

Volume = 100 × 12 × 28 × 12 × 5 × 10⁻⁶

Volume = 2.016 in³

In cubic centimeters, we have:

Volume = 2.016 × 2.54³

Volume = 33.04 cubic centimeters.

Next, we would determine the mass of gold required:

Mass = Density × Volume

Mass = 19.32 × 33.04

Mass = 638.33 grams.

Converting the mass in grams to troy ounces, we have:

Mass = 638.33/31.1035

Mass = 20.52 troy ounce

Now, we can determine the total cost of gold needed:

Total cost of gold = 20.52 × $1654

Total cost of gold = $33,940.08.

Read more on cost and density here: https://brainly.com/question/13138330

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