Answer :
At a point on the ground 15ft from the base of a tree, the distance to the top of the tree is 1 ft more than 2 times the height of the tree. Find the height of the tree.
The height of the tree is 8ft.
Given that,
A right triangle has two legs, which are height and (15 feet) from the base.
The hypotenuse is 15 feet from the base to the top of the tree.
or 2(height) + 1ft.
Let us take a as height of the tree; b=distance from base=15 ft; c=hypotenuse=2a+1ft
The area of the square created on the hypotenuse of any right triangle is equal to the sum of the areas of the squares formed on the triangle's legs:
[tex]a^{2} +b^{2} =c^{2}[/tex]
[tex]a^{2} +(15ft)^{2}=(2a+ 1ft) ^{2}[/tex]
[tex]a^{2} +225ft^{2}=4a^{2} +4a+1\\ 0=3a^{2}+4a-224\\ 0=(a-8)\times(3a+28)\\[/tex]
Now,
a-8=0 (or) 3a+28=0
a=8 (or) a=[tex]\frac{-28}{3}[/tex]
Therefore, The height of the tree is 8ft.
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