The total surface areas of a cone of a base radius r and perpendicular height h is given by s=(22/7)*r^2 + (22/7)*(r^2)*√((r^2)+(h^2).if r and h are each increasing at the rate of 0.5m/s and 0.2m/s respectively,find the rate at which s is increasing at the instant when r=3m and h=4m