Answer:
[tex]\dfrac{1}{3}[/tex]
Step-by-step explanation:
[tex]\boxed{\begin{minipage}{4.3cm}\begin{center}\underline{Slope of a line}\end{center}\\\\\begin{center}$m=\dfrac{y_2-y_1}{x_2-x_1}$\end{center}\\\\\\\begin{center}where $(x_1,y_1)$ and $(x_2,y_2)$\\are two points on the line.\end{center}\end{minipage}}[/tex]
Define two points on the line of the given graph:
- [tex]\text{Let}\:(x_1,y_1)=(-3,-2)[/tex]
- [tex]\text{Let}\:(x_2,y_2)=(3,0)[/tex]
Substitute the defined points into the slope formula:
[tex]\implies m=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{0-(-2)}{3-(-3)}=\dfrac{2}{6}=\dfrac{1}{3}[/tex]
Therefore, the slope of the line is ¹/₃.
