Answered

The polynomial of degree 4, P(x), has a root of multiplicity 2 at x = 3 and roots of multiplicity 1 at x = 0 and x =-2. It goes through the point (5, 70). Find a formula for P(x).
P(x) =

The polynomial of degree 4 Px has a root of multiplicity 2 at x 3 and roots of multiplicity 1 at x 0 and x 2 It goes through the point 5 70 Find a formula for P class=


Answer :

varshamittal029

The answer to this question is:

y = 1/2( x - 0 )( x - 3)( x - 3 )( x - (-2))

A degree four polynomial will have the root form.:

y = k( x-r₁ )( x-r₂ )( x-r₃ )( x-r₄ )

Use the point to determine the value of k after the values are substituted for the roots.

y = k( x - 0 )( x - 3)( x - 3 )( x - (-2))

Figure out the value of k using the point (5,70).:

70 = k( 5 - 0 )( 5 - 3)( 5 - 3 )( 5 - (-2))

70 = k(5)(2)(2)(7)

k = 70/5*2*2*7

  = 70/140

  = 1/2

The polynomial's root form is:

y = 1/2( x - 0 )( x - 3)( x - 3 )( x - (-2))

Therefore, the formula for P(x) =  y = 1/2( x - 0 )( x - 3)( x - 3 )( x - (-2))

Learn more about Polynomial here: https://brainly.com/question/2833285

#SPJ9

Other Questions