The equation of the line that passes through the given point and is parallel to the given line is y = -(1/2)x - 2
Given the data in the question;
Since the equation is already in slope intercept form, compare with slope intercept formula to determine the slope and y-intercept. y = mx + b.
y = -(1/2)x + 6
y = mx + b
Slope m = -(1/2)
b = 6
Now, to determine the equation parallel, the slopes must equal.
We can do this using the point-slope formula.
y - y₁ = m( x - x₁ )
Substitute Slope m -(1/2) and point (0, −2) into the formula
y - (-2) = -(1/2)( x - 0 )
y + 2 = -(1/2)x
y = -(1/2)x - 2
Therefore, the equation of the line that passes through the given point and is parallel to the given line is y = -(1/2)x - 2
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