The slope-intercept form of the equation of the line described is y = -10/9x + 4/3.
Given the following data:
Points on x-axis = (-6, 4).
Points on y-axis = (8, -1).
A slope is also referred to as gradient and it's typically used to describe both the ratio, direction and steepness of the function of a straight line.
Mathematically, the slope of any straight line can be calculated by using this formula;
[tex]Slope = \frac{Change\;in\;y\;axis}{Change\;in\;x\;axis}\\\\Slope = \frac{y_2\;-\;y_1}{x_2\;-\;x_1}[/tex]
Substituting the given points into the formula, we have;
Slope = (4 + 6)/-1 - 8)
Slope = -10/9
Mathematically, the standard form of the equation of a straight line is given by;
y = mx + c
Where:
At point (-6, 8), we have:
8 = -10/9(-6) + c
8 = 60/9 + c
72 = 60 + 9c
9c = 72 - 60
c = 12/9
c = 4/3
Therefore, the slope-intercept form of the equation of the line described is y = -10/9x + 4/3.
Read more on slope-intercept form here: brainly.com/question/1884491
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