Find the equation of a line that contains the points (−6,8) and (4,−1). Write the equation in slope-intercept form, using fractions when required.



Answer :

Lanuel

The slope-intercept form of the equation of the line described is y = -10/9x + 4/3.

Given the following data:

Points on x-axis = (-6, 4).

Points on y-axis = (8, -1).

What is a slope?

A slope is also referred to as gradient and it's typically used to describe both the ratio, direction and steepness of the function of a straight line.

How to calculate the slope of a line?

Mathematically, the slope of any straight line can be calculated by using this formula;

[tex]Slope = \frac{Change\;in\;y\;axis}{Change\;in\;x\;axis}\\\\Slope = \frac{y_2\;-\;y_1}{x_2\;-\;x_1}[/tex]

Substituting the given points into the formula, we have;

Slope = (4 + 6)/-1 - 8)

Slope = -10/9

Mathematically, the standard form of the equation of a straight line is given by;

y = mx + c

Where:

  • x and y are the points.
  • m is the slope.
  • c is the intercept.

At point (-6, 8), we have:

8 = -10/9(-6) + c

8 = 60/9 + c

72 = 60 + 9c

9c = 72 - 60

c = 12/9

c = 4/3

Therefore, the slope-intercept form of the equation of the line described is y = -10/9x + 4/3.

Read more on slope-intercept form here: brainly.com/question/1884491

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