Answer: y=2x-2
Step-by-step explanation:
X intercept is 1
Hence,
(1,0)
Thus,
(1,0) (-1.-4)
Equation of a straight line:
[tex]\displaystyle\\\boxed {\frac{x-x_1}{x_2-x_1}=\frac{y-y_1}{y_2-y_1} }[/tex]
x₁=1 x₂=-1 y₁=0 y₂=-4
[tex]\displaystyle\\\frac{x-1}{-1-1} =\frac{y-0}{-4-0} \\\\\frac{x-1}{-2} =\frac{y}{-4} \\\\[/tex]
Multiply both parts of the equation by -4:
(2)(x-1)=y
2x-2=y
Answer:
[tex]y=2x-2[/tex]
Step-by-step explanation:
The x-intercept is when the line crosses the x-axis, so when y = 0.
Therefore, the two points on the line are:
To find the equation of the line when given two points from the line, first find the slope:
[tex]\textsf{slope}\:(m)=\dfrac{\textsf{change in $y$}}{\textsf{change in $x$}}=\dfrac{-4-0}{-1-1}=2[/tex]
Now substitute the found slope and one of the points (1, 0) into the point-slope form of a linear equation:
[tex]\implies y-y_1=m(x-x_1)[/tex]
[tex]\implies y-0=2(x-1)[/tex]
[tex]\implies y=2x-2[/tex]
Therefore, the equation of the line is:
[tex]y=2x-2[/tex]