Rearranging the equation to solve for the variables gives;
v = d - at^2/t
a = 2d - 2vt/t^2
Given the equation;
d = vt + 1/2 at^2
Let's solve for v
First, collect like terms
vt = d - 1/2 at^2
Now, divide both sides by the coefficient of v which is 't', we have;
vt/t = d - at^2/t
v =
[tex] \frac{d - a {t}^{2} }{t} [/tex]
Let's solve for a
d - vt = at^2/2
cross multiply
2( d - vt) = at^2
expand the bracket
2d - 2vt = at^2
divide both sides by the coefficient of a which is t^2, we have;
2d - 2vt /t^2 = a
a = 2d - 2vt/t^2
Thus, rearranging the equation to solve for the variables gives v = d - at^2/t and a = 2d - 2vt/t^2 respectively.
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