6. The amount of carbon-14 left / years after the death of an organism is given by
2(1) = Que-0.0001221
where Qo is the amount left at the time of death. For this problem, assume Qo=
6.0 x 1010 carbon-14 atoms.
(a) How much is left after 50,000 years? What fraction of the original amount is this?
(b) How much is left after 100,000 years? What fraction of the original amount is
this?
(c) What is the half-life of carbon-14?
(d) About how many half-lives will occur in 50,000 years? Roughly what fraction will
be left? How does this compare to your answer in part (a)?



Answer :

The half-life of carbon-14 is 5,730 years. Assuming you start with 100% of carbon-14, what is the expression for the percent, P(t), of carbon-14 that remains in an organism that is t years old and what is the percent of carbon-14 remaining (rounded to the nearest whole percent) in an organism estimated to be 20,000 years old

Carbon-14, C-14, 14

C or radiocarbon, is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons. Its presence in organic materials is the basis of the radiocarbon dating method pioneered by Willard Libby and colleagues (1949) to date archaeological, geological and hydrogeological samples. Carbon-14 was discovered on February 27, 1940, by Martin Kamen and Sam Ruben at the University of California Radiation Laboratory in Berkeley, California. Its existence had been suggested by Franz Kurie in 1934.[2]

There are also trace amounts of the unstable radioisotope carbon-14 (14C) on Earth. Carbon-14 has a relatively short half-life of 5,730 years, meaning that the fraction of carbfon-14 in a sample is halved over the course of 5,730 years due to radioactive decay to nitrogen-14.

To know more about carbon14

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