The price of the cheaper vehicle is $39,000
Calculating Cost
From the question, we are to determine the price of the cheaper vehicle
Let the cost of one of the cars b $x
and the cost of the other car be $y
From the given information,
The total price for two cars at a dealership is $108,000
That is
x + y = 108000 ----------- (1)
and
one car’s price is $9000 less than twice the other
x = 2y - 9000 ----------- (2)
Put equation (2) into equation (1)
x + y = 108000
2y - 9000 + y = 108000
2y + y - 9000 = 108000
2y + y = 108000 + 9000
3y = 117000
y = 117000/3
y = 39000
∴ The price of one of the vehicles is $39,000
Substitute this value into equation (2)
x = 2y - 9000
x = 2(39000) - 9000
x = 78000 - 9000
x = 69000
The price of the other vehicle is $69,000
Hence, the price of the cheaper vehicle is $39,000
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