Answer :
The force of attraction would be 1.5 x [tex]10^{-10}[/tex] N
Calculation
According to Coulomb's law constant,
k = 9 x [tex]10^{9}[/tex] N[tex]m^{2}[/tex]/[tex]C^{2}[/tex]
The magnitude of the charge of an electron is
e= 1.6 x [tex]10^{9}[/tex] C
The magnitude of the electric force (F) between the cation and the anion is given by
F = k[tex]\frac{Q^2}{d^2}[/tex]
= k [tex]2e^{2}[/tex]/[tex]d^{2}[/tex]
= (9 x [tex]10^{9}[/tex] N[tex]m^{2}[/tex]/[tex]C^{2}[/tex]) x [tex]10^{9}[/tex] x {2x (1.6 x [tex]10^{-19})^{2}[/tex]}/ (2.5[tex])^{2}[/tex]
= 1.5 x x [tex]10^{-10}[/tex] N
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